HRWP36p78
To solve this problem, you have to do a bunch of steps. I'm listing the steps to part a in reverse order since that is how you would need to tackle the problem:
To solve this problem, you have to do a bunch of steps. I'm listing the steps to part a in reverse order since that is how you would need to tackle the problem:
- To find d, you need the horizontal speed (vx) since
d = (vx) t and t=4s. - To find vx, you need the total velocity (v) when it lands on
the roof (because vx = v cos(60°)) - To find v, you need to find the vertical velocity (vy) when it
lands on the roof. - To find the final vertical velocity (vy), you need the initial
vertical velocity (vy0). - To find vy0, use the acceleration equation:
h = .5 g t2 + vy0 t - Now, you can find vy since vy = vy0 + gt
- Next, you can find v since vy = v sin(60°)
- Going backwards, you can find d.
- Parts b and c are easy since you already have vy0 and
vx (it's the usual translation from cartesian to polar coordinates).
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