HRWP49p79
In uniform circular motion, the magnitude of the acceleration is v2/r. Since v = 2π r/T then a = 4π2 r/T2. Now we see that for any object on the merry-go-round, the magnitude of the acceleration depends linearly on r. Since multiplying a vector by a scalar does not change the direction of the vector, objects along a single radial line will have accelerations which only differ by a scalar quantity.
In uniform circular motion, the magnitude of the acceleration is v2/r. Since v = 2π r/T then a = 4π2 r/T2. Now we see that for any object on the merry-go-round, the magnitude of the acceleration depends linearly on r. Since multiplying a vector by a scalar does not change the direction of the vector, objects along a single radial line will have accelerations which only differ by a scalar quantity.
posted by Dr9pt8 at 8:03 PM
0 Comments:
Post a Comment
<< Home