HRWP15p298
The linear acceleration of the yo-yo is the same as the center-of-mass acceleration (because we assume the yo-yo is going straight down). You also have to assume that the string is rolling directly off the axle. That way, when you use the relationship which ties angular motion to linear motion, a = α r, you use r = radius of axle, not the radius of the yo-yo.
The linear acceleration of the yo-yo is the same as the center-of-mass acceleration (because we assume the yo-yo is going straight down). You also have to assume that the string is rolling directly off the axle. That way, when you use the relationship which ties angular motion to linear motion, a = α r, you use r = radius of axle, not the radius of the yo-yo.
posted by Dr9pt8 at 2:56 PM
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